What is (Y-1)^2+(X+5)^2=1 ?

The solution to (Y-1)^2+(X+5)^2=1 is Circle with (a,b)=(1,-5),r=1

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(Y-1)^2+(X+5)^2=1

(Y - 1)^{2} + (X + 5)^{2} = 1

(a, b) = (1, - 5), r = 1

Solution steps

(Y - 1)^{2} + (X + 5)^{2} = 1

Rewrite

(Y - 1)^{2} + (X + 5)^{2} = 1

in the form of the standard circle equation

(Y - 1)^{2} + (X - (- 5))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, - 5), r = 1

(x + 2)^{2} + (y - 1)^{2} = 2^{2}

0 + y^{2} + z^{2} = 1

(x - 2)^{2} + (y - 17)^{2} = 64

(x + 5)^{2} + (y - 1)^{2} = 7

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

What is (Y-1)^2+(X+5)^2=1 ?
The solution to (Y-1)^2+(X+5)^2=1 is Circle with (a,b)=(1,-5),r=1