What is the radius (x+3)^2+(y-4)^2=16 ?

The radius (x+3)^2+(y-4)^2=16 is r=4

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radius (x+3)^2+(y-4)^2=16

radius

(x + 3)^{2} + (y - 4)^{2} = 16

r = 4

Solution steps

(x + 3)^{2} + (y - 4)^{2} = 16

Rewrite

(x + 3)^{2} + (y - 4)^{2} = 16

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 4

And the radius is:

r = 4

(x - 2)^{2} + (y - 5)^{2} = 106

4 x^{2} + 4 y^{2} - 12 x + 4 y - 26 = 0

4 x^{2} + 4 y^{2} + 8 x - y = 0

(x - 2)^{2} + (y - 3)^{2} = 64

x^{2} + (y + 2)^{2} = (20^{2})