What is the circumference x^2+y^2-10x+6y=0 ?

The circumference x^2+y^2-10x+6y=0 is C=2sqrt(34)pi

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circumference x^2+y^2-10x+6y=0

circumference

x^{2} + y^{2} - 10 x + 6 y = 0

C = 234 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 10 x + 6 y = 0 : r = 34

C = 234 π

4 x^{2} + 4 y^{2} - 8 x + 24 y = 24

x^{2} + y^{2} + 4 x - 10 y + 13 = 0

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0

x^{2} + y^{2} - 10 x - 6 y + 9 = 0

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

What is the circumference x^2+y^2-10x+6y=0 ?
The circumference x^2+y^2-10x+6y=0 is C=2sqrt(34)pi