What is the circumference 9x^2+9y^2-6x-2y-17=0 ?

The circumference 9x^2+9y^2-6x-2y-17=0 is C=(2sqrt(163)pi)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference 9x^2+9y^2-6x-2y-17=0

circumference

9 x^{2} + 9 y^{2} - 6 x - 2 y - 17 = 0

C = \frac{2 163 π}{9}

Solution steps

C = 2 π r

Find the radius

Radius given

9 x^{2} + 9 y^{2} - 6 x - 2 y - 17 = 0 : r = \frac{163}{9}

C = 2 π \frac{163}{9}

Refine

C = \frac{2 163 π}{9}

x^{2} + y^{2} + 8 x - 4 y + 4 = 0

(x + 1)^{2} + (y + 1)^{2} = 13

(x - 3)^{2} + (y - 1)^{2} = 4

4 x^{2} + 4 y^{2} + 20 x - 8 y + 9 = 0

x^{2} + y^{2} \leq 4^{2}

What is the circumference 9x^2+9y^2-6x-2y-17=0 ?
The circumference 9x^2+9y^2-6x-2y-17=0 is C=(2sqrt(163)pi)/9