What is the asymptotes of (y^2)/4-(x+1)^2=1 ?

The asymptotes of (y^2)/4-(x+1)^2=1 is y=2(x+1),\quad y=-2(x+1)

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asymptotes of (y^2)/4-(x+1)^2=1

asymptotes

\frac{y ^{2}}{4} - (x + 1)^{2} = 1

y = 2 (x + 1), y = - 2 (x + 1)

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{4} - (x + 1)^{2} = 1 :

Up-down Hyperbola with

(h, k) = (- 1, 0), a = 2, b = 1

y = \frac{2}{1} (x - (- 1)) + 0, y = - \frac{2}{1} (x - (- 1)) + 0

Refine

y = 2 (x + 1), y = - 2 (x + 1)

y^{2} - 4 y - 8 x - 12 = 0

f (x) = x^{2} - 5 x

3 x^{2} + 2 y = 26

y^{2} = - 2 x

x^{2} + y^{2} - 4 x + 10 y + 13 = 0

What is the asymptotes of (y^2)/4-(x+1)^2=1 ?
The asymptotes of (y^2)/4-(x+1)^2=1 is y=2(x+1),\quad y=-2(x+1)