What is (((x+1)^2))/3+(((y+1)^2))/4 =1 ?

The solution to (((x+1)^2))/3+(((y+1)^2))/4 =1 is Ellipse with (h,k)=(-1,-1),a=sqrt(3),b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(((x+1)^2))/3+(((y+1)^2))/4 =1

\frac{( ( x + 1 ) ^{2} )}{3} + \frac{( ( y + 1 ) ^{2} )}{4} = 1

(h, k) = (- 1, - 1), a = 3, b = 2

Solution steps

\frac{( x + 1 ) ^{2}}{3} + \frac{( y + 1 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{3} + \frac{( y + 1 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{( 3 ) ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 1), a = 3, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 1), b = 2, a = 3

2 - 1 = x^{2} + 3 y^{2}

- 25 x^{2} - 4 y^{2} = - 100

\frac{( x + 4 ) ^{2}}{49} + \frac{( y - 4 ) ^{2}}{25} = 1

y^{2} + \frac{x ^{2}}{4} = 1

f, f = 3 - x f (x)^{- 1} (x)

What is (((x+1)^2))/3+(((y+1)^2))/4 =1 ?
The solution to (((x+1)^2))/3+(((y+1)^2))/4 =1 is Ellipse with (h,k)=(-1,-1),a=sqrt(3),b=2