What is the vertices 25x^2+4y^2=100 ?

The vertices 25x^2+4y^2=100 is (0,5),(0,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 25x^2+4y^2=100

vertices

25 x^{2} + 4 y^{2} = 100

(0, 5), (0, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + 4 y^{2} = 100 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 2

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

5 x^{2} + 2 y^{2} = 50

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

3 x^{2} + y^{2} = 84

25 x^{2} + y^{2} - 100 x + 8 y + 91 = 0

What is the vertices 25x^2+4y^2=100 ?
The vertices 25x^2+4y^2=100 is (0,5),(0,-5)