What is the foci (x^2)/(81)+(y^2)/(49)=1 ?

The foci (x^2)/(81)+(y^2)/(49)=1 is (4sqrt(2),0),(-4sqrt(2),0)

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foci (x^2)/(81)+(y^2)/(49)=1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{49} = 1

(42, 0), (- 42, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 7^{2} : 42

(0 + 42, 0), (0 - 42, 0)

Refine

(42, 0), (- 42, 0)

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

x^{2} + 2 y^{2} - 2 x + 8 y + 5 = 0

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1

What is the foci (x^2)/(81)+(y^2)/(49)=1 ?
The foci (x^2)/(81)+(y^2)/(49)=1 is (4sqrt(2),0),(-4sqrt(2),0)