What is the foci (x^2)/(64)+(y^2)/(100)=1 ?

The foci (x^2)/(64)+(y^2)/(100)=1 is (0,6),(0,-6)

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foci (x^2)/(64)+(y^2)/(100)=1

foci

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

(0, 6), (0, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

x^{2} + 2 y^{2} - 2 x + 8 y + 5 = 0

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1

What is the foci (x^2)/(64)+(y^2)/(100)=1 ?
The foci (x^2)/(64)+(y^2)/(100)=1 is (0,6),(0,-6)