What is the foci ((x-1)^2)/2+(y^2)/1 =1 ?

The foci ((x-1)^2)/2+(y^2)/1 =1 is (2,0),(0,0)

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foci ((x-1)^2)/2+(y^2)/1 =1

foci

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

(2, 0), (0, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (1, 0), a = 2, b = 1

(1 + c, 0), (1 - c, 0)

Compute

c :

c = 2^{2} - 1^{2} : 1

(1 + 1, 0), (1 - 1, 0)

Refine

(2, 0), (0, 0)

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

25 x^{2} + 16 y^{2} = 400

What is the foci ((x-1)^2)/2+(y^2)/1 =1 ?
The foci ((x-1)^2)/2+(y^2)/1 =1 is (2,0),(0,0)