What is the foci ((x+8)^2)/(169)+((y+9)^2)/(25)=1 ?

The foci ((x+8)^2)/(169)+((y+9)^2)/(25)=1 is (4,-9),(-20,-9)

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foci ((x+8)^2)/(169)+((y+9)^2)/(25)=1

foci

\frac{( x + 8 ) ^{2}}{169} + \frac{( y + 9 ) ^{2}}{25} = 1

(4, - 9), (- 20, - 9)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x + 8 ) ^{2}}{169} + \frac{( y + 9 ) ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (- 8, - 9), a = 13, b = 5

(- 8 + c, - 9), (- 8 - c, - 9)

Compute

c :

c = 1 3^{2} - 5^{2} : 12

(- 8 + 12, - 9), (- 8 - 12, - 9)

Refine

(4, - 9), (- 20, - 9)

9 x^{2} + 25 y^{2} + 36 x + 250 y = - 436

\frac{x ^{2}}{2} + \frac{y ^{2}}{4} = 1

x^{2} + \frac{y ^{2}}{4} = 1

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

\frac{x ^{2}}{4} + y^{2} = 1

What is the foci ((x+8)^2)/(169)+((y+9)^2)/(25)=1 ?
The foci ((x+8)^2)/(169)+((y+9)^2)/(25)=1 is (4,-9),(-20,-9)