What is the foci 9x^2+16y^2-72x+64y-368=0 ?

The foci 9x^2+16y^2-72x+64y-368=0 is (4+2sqrt(7),-2),(4-2sqrt(7),-2)

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foci 9x^2+16y^2-72x+64y-368=0

foci

9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0

(4 + 27, - 2), (4 - 27, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0 :

Ellipse with center

(h, k) = (4, - 2), a = 8, b = 6

(4 + c, - 2), (4 - c, - 2)

Compute

c :

c = 8^{2} - 6^{2} : 27

(4 + 27, - 2), (4 - 27, - 2)

7 x^{2} + 2 y^{2} = 14

25 x^{2} + 36 y^{2} = 900

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 4 ) ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{5} = 1

4 x^{2} + 25 y^{2} - 50 y = 75

What is the foci 9x^2+16y^2-72x+64y-368=0 ?
The foci 9x^2+16y^2-72x+64y-368=0 is (4+2sqrt(7),-2),(4-2sqrt(7),-2)