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Popular >

foci 7x^2+2y^2=14

Solution

foci

7 x^{2} + 2 y^{2} = 14

Solution

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

7 x^{2} + 2 y^{2} = 14 :

Ellipse with center

(h, k) = (0, 0), b = 7, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 7^{2} - 2^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

Popular Examples

foci 25x^2+36y^2=900 foci

25 x^{2} + 36 y^{2} = 900

foci ((x-3)^2}{16}+\frac{(y+4)^2)/9 =1 foci

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 4 ) ^{2}}{9} = 1

foci ((x-1)^2)/9+((y-1)^2)/5 =1 foci

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{5} = 1

foci 4x^2+25y^2-50y=75 foci

4 x^{2} + 25 y^{2} - 50 y = 75

foci x^2+4y^2-16=0 foci

x^{2} + 4 y^{2} - 16 = 0

Frequently Asked Questions (FAQ)

What is the foci 7x^2+2y^2=14 ?
The foci 7x^2+2y^2=14 is (0,sqrt(5)),(0,-sqrt(5))