What is the foci 25x^2+16y^2+100x+96y-156=0 ?

The foci 25x^2+16y^2+100x+96y-156=0 is (-2,0),(-2,-6)

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foci 25x^2+16y^2+100x+96y-156=0

foci

25 x^{2} + 16 y^{2} + 100 x + 96 y - 156 = 0

(- 2, 0), (- 2, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 16 y^{2} + 100 x + 96 y - 156 = 0 :

Ellipse with center

(h, k) = (- 2, - 3), b = 5, a = 4

(- 2, - 3 + c), (- 2, - 3 - c)

Compute

c :

c = 5^{2} - 4^{2} : 3

(- 2, - 3 + 3), (- 2, - 3 - 3)

Refine

(- 2, 0), (- 2, - 6)

9 x^{2} + 16 y^{2} + 64 y - 80 = 0

4 x^{2} + y^{2} = 4 x

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{25} = 1

What is the foci 25x^2+16y^2+100x+96y-156=0 ?
The foci 25x^2+16y^2+100x+96y-156=0 is (-2,0),(-2,-6)