What is the foci (x^2}{12}+\frac{y^2)/6 =1 ?

The foci (x^2}{12}+\frac{y^2)/6 =1 is (sqrt(6),0),(-sqrt(6),0)

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foci (x^2}{12}+\frac{y^2)/6 =1

foci

\frac{x ^{2}}{12} + \frac{y ^{2}}{6} = 1

(6, 0), (- 6, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{12} + \frac{y ^{2}}{6} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 23, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (23)^{2} - 6^{2} : 6

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

\frac{( x + 4 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{16} = 1

\frac{( x - 4 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{100} = 1

x^{2} + 4 y^{2} - 6 x + 16 y + 21 = 0

\frac{x ^{2}}{64} + \frac{y ^{2}}{15} = 1

What is the foci (x^2}{12}+\frac{y^2)/6 =1 ?
The foci (x^2}{12}+\frac{y^2)/6 =1 is (sqrt(6),0),(-sqrt(6),0)