What is the foci (x^2)/(81)+(y^2)/(100)=1 ?

The foci (x^2)/(81)+(y^2)/(100)=1 is (0,sqrt(19)),(0,-sqrt(19))

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foci (x^2)/(81)+(y^2)/(100)=1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{100} = 1

(0, 19), (0, - 19)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{100} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 9

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 0^{2} - 9^{2} : 19

(0, 0 + 19), (0, 0 - 19)

Refine

(0, 19), (0, - 19)

x^{2} + 4 y^{2} - 6 x + 16 y + 21 = 0

\frac{x ^{2}}{64} + \frac{y ^{2}}{15} = 1

4 x^{2} + 24 x + 25 y^{2} + 200 y + 336 = 0

\frac{( x + 1 ) ^{2}}{10} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{( x ) ^{2}}{44} + \frac{y ^{2}}{125} = 1

What is the foci (x^2)/(81)+(y^2)/(100)=1 ?
The foci (x^2)/(81)+(y^2)/(100)=1 is (0,sqrt(19)),(0,-sqrt(19))