What is the foci 25x^2+16y^2+100x-300=0 ?

The foci 25x^2+16y^2+100x-300=0 is (-2,3),(-2,-3)

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foci 25x^2+16y^2+100x-300=0

foci

25 x^{2} + 16 y^{2} + 100 x - 300 = 0

(- 2, 3), (- 2, - 3)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 16 y^{2} + 100 x - 300 = 0 :

Ellipse with center

(h, k) = (- 2, 0), b = 5, a = 4

(- 2, 0 + c), (- 2, 0 - c)

Compute

c :

c = 5^{2} - 4^{2} : 3

(- 2, 0 + 3), (- 2, 0 - 3)

Refine

(- 2, 3), (- 2, - 3)

\frac{x ^{2}}{121} + \frac{( y + 4 ) ^{2}}{23} = 1

\frac{x ^{2} + y ^{2}}{5} = 1

\frac{( x - 2 ) ^{2}}{16} + \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{8} + \frac{y ^{2}}{5} = 1

16 x^{2} + 25 y^{2} - 96 x + 100 y - 156 = 0

What is the foci 25x^2+16y^2+100x-300=0 ?
The foci 25x^2+16y^2+100x-300=0 is (-2,3),(-2,-3)