What is the foci 16x^2+25y^2-96x+100y-156=0 ?

The foci 16x^2+25y^2-96x+100y-156=0 is (6,-2),(0,-2)

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foci 16x^2+25y^2-96x+100y-156=0

foci

16 x^{2} + 25 y^{2} - 96 x + 100 y - 156 = 0

(6, - 2), (0, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} - 96 x + 100 y - 156 = 0 :

Ellipse with center

(h, k) = (3, - 2), a = 5, b = 4

(3 + c, - 2), (3 - c, - 2)

Compute

c :

c = 5^{2} - 4^{2} : 3

(3 + 3, - 2), (3 - 3, - 2)

Refine

(6, - 2), (0, - 2)

+ \frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{25} = 1

81 x^{2} + 64 y^{2} = 5184

x^{2} + 2 y^{2} - 8 y + 4 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{64} = 1

What is the foci 16x^2+25y^2-96x+100y-156=0 ?
The foci 16x^2+25y^2-96x+100y-156=0 is (6,-2),(0,-2)