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Popular >

foci (x^2+y^2)/5 =1

Solution

foci

\frac{x ^{2} + y ^{2}}{5} = 1

Solution

(0, 0), (0, 0)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2} + y ^{2}}{5} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 5

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 5^{2} : 0

(0, 0 + 0), (0, 0 - 0)

Refine

(0, 0), (0, 0)

Popular Examples

foci ((x-2)^2}{16}+\frac{y^2)/9 =1 foci

\frac{( x - 2 ) ^{2}}{16} + \frac{y ^{2}}{9} = 1

foci (x^2)/8+(y^2)/5 =1 foci

\frac{x ^{2}}{8} + \frac{y ^{2}}{5} = 1

foci 16x^2+25y^2-96x+100y-156=0 foci

16 x^{2} + 25 y^{2} - 96 x + 100 y - 156 = 0

foci+(x^2}{16}+\frac{y^2)/4 =1 foci

+ \frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

foci (x^2)/(81)+(y^2)/(25)=1 foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{25} = 1

Frequently Asked Questions (FAQ)

What is the foci (x^2+y^2)/5 =1 ?
The foci (x^2+y^2)/5 =1 is (0,0),(0,0)