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Popular >

foci x^2+2y^2-8y+4=0

Solution

foci

x^{2} + 2 y^{2} - 8 y + 4 = 0

Solution

(2, 2), (- 2, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

x^{2} + 2 y^{2} - 8 y + 4 = 0 :

Ellipse with center

(h, k) = (0, 2), a = 2, b = 2

(0 + c, 2), (0 - c, 2)

Compute

c :

c = 2^{2} - 2^{2} : 2

(0 + 2, 2), (0 - 2, 2)

Refine

(2, 2), (- 2, 2)

Popular Examples

foci (x^2)/(36)+(y^2)/(64)=1 foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{64} = 1

foci (x^2)/(16)+y^2=1 foci

\frac{x ^{2}}{16} + y^{2} = 1

foci 18x^2+4y^2-72x+4y+37=0 foci

18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

foci 16x^2+25y^2+64x-200y+64=0 foci

16 x^{2} + 25 y^{2} + 64 x - 200 y + 64 = 0

foci (x^2)/(49)+(y^2)/(169)=1 foci

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

Frequently Asked Questions (FAQ)

What is the foci x^2+2y^2-8y+4=0 ?
The foci x^2+2y^2-8y+4=0 is (sqrt(2),2),(-sqrt(2),2)