What is the foci (x^2)/9+(y^2)/(81)=1 ?

The foci (x^2)/9+(y^2)/(81)=1 is (0,6sqrt(2)),(0,-6sqrt(2))

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foci (x^2)/9+(y^2)/(81)=1

foci

\frac{x ^{2}}{9} + \frac{y ^{2}}{81} = 1

(0, 62), (0, - 62)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 9^{2} - 3^{2} : 62

(0, 0 + 62), (0, 0 - 62)

Refine

(0, 62), (0, - 62)

16 xx + 25 yy = 400

16 x^{2} + 4 y^{2} - 32 x + 24 y - 12 = 0

16 x^{2} + 25 y^{2} - 64 x - 336 = 0

\frac{( x ) ^{2}}{25} + \frac{y ^{2}}{16} = 1

x^{2} + 4 y^{2} - 64 = 0

What is the foci (x^2)/9+(y^2)/(81)=1 ?
The foci (x^2)/9+(y^2)/(81)=1 is (0,6sqrt(2)),(0,-6sqrt(2))