What is the foci 9x^2+25y^2+54x+100y-44=0 ?

The foci 9x^2+25y^2+54x+100y-44=0 is (1,-2),(-7,-2)

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foci 9x^2+25y^2+54x+100y-44=0

foci

9 x^{2} + 25 y^{2} + 54 x + 100 y - 44 = 0

(1, - 2), (- 7, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 54 x + 100 y - 44 = 0 :

Ellipse with center

(h, k) = (- 3, - 2), a = 5, b = 3

(- 3 + c, - 2), (- 3 - c, - 2)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 3 + 4, - 2), (- 3 - 4, - 2)

Refine

(1, - 2), (- 7, - 2)

15 x^{2} + 16 y^{2} = 240

\frac{( x - 3 ) ^{2}}{49} + \frac{( y - 5 ) ^{2}}{4} = 1

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 2 ) ^{2}}{20} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{16} = 1

\frac{( x + 4 ) ^{2}}{5} + \frac{( y - 5 ) ^{2}}{9} = 1

What is the foci 9x^2+25y^2+54x+100y-44=0 ?
The foci 9x^2+25y^2+54x+100y-44=0 is (1,-2),(-7,-2)