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Popular >

foci 15x^2+16y^2=240

Solution

foci

15 x^{2} + 16 y^{2} = 240

Solution

(1, 0), (- 1, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

15 x^{2} + 16 y^{2} = 240 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 15

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} - 15^{2} : 1

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

Popular Examples

foci ((x-3)^2}{49}+\frac{(y-5)^2)/4 =1 foci

\frac{( x - 3 ) ^{2}}{49} + \frac{( y - 5 ) ^{2}}{4} = 1

foci ((x-1)^2)/(45)+((y-2)^2)/(20)=1 foci

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 2 ) ^{2}}{20} = 1

foci (x^2)/(100)+(y^2)/(16)=1 foci

\frac{x ^{2}}{100} + \frac{y ^{2}}{16} = 1

foci ((x+4)^2)/5+((y-5)^2)/9 =1 foci

\frac{( x + 4 ) ^{2}}{5} + \frac{( y - 5 ) ^{2}}{9} = 1

foci (x^2)/1+(y^2)/(64)=1 foci

\frac{x ^{2}}{1} + \frac{y ^{2}}{64} = 1

Frequently Asked Questions (FAQ)

What is the foci 15x^2+16y^2=240 ?
The foci 15x^2+16y^2=240 is (1,0),(-1,0)