What is the axis (x^2}{36}+\frac{y^2)/4 =1 ?

The axis (x^2}{36}+\frac{y^2)/4 =1 is semi-major axis a=6, semi-minor axis b=2

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axis (x^2}{36}+\frac{y^2)/4 =1

axis

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

semi - major axis a = 6, semi - minor axis b = 2

Solution steps

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 2

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

25 x^{2} + 9 y^{2} = 225

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

What is the axis (x^2}{36}+\frac{y^2)/4 =1 ?
The axis (x^2}{36}+\frac{y^2)/4 =1 is semi-major axis a=6, semi-minor axis b=2