What is the axis ((x-8)^2)/(49)+((y+1)^2)/(100)=1 ?

The axis ((x-8)^2)/(49)+((y+1)^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=7

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axis ((x-8)^2)/(49)+((y+1)^2)/(100)=1

axis

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{100} = 1

semi - major axis b = 10, semi - minor axis a = 7

Solution steps

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{100} = 1

Rewrite

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - 8 ) ^{2}}{7 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (8, - 1), a = 7, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (8, - 1), b = 10, a = 7

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{16} + (y - 4)^{2} = 1

49 x^{2} + 64 y^{2} = 25

\frac{x ^{2}}{9} + (y - 1)^{2} = 1

9 x^{2} + 16 y^{2} - 144 = 0

What is the axis ((x-8)^2)/(49)+((y+1)^2)/(100)=1 ?
The axis ((x-8)^2)/(49)+((y+1)^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=7