What is -f(x)=4x^2+4x-3 ?

The solution to -f(x)=4x^2+4x-3 is Parabola with (h,k)=(-1/2 ,4),p=-1/16

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-f(x)=4x^2+4x-3

- f (x) = 4 x^{2} + 4 x - 3

(h, k) = (- \frac{1}{2}, 4), p = - \frac{1}{16}

Solution steps

- y = 4 x^{2} + 4 x - 3

Rewrite

- y = 4 x^{2} + 4 x - 3

in the standard form

4 (- \frac{1}{16}) (y - 4) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, 4), p = - \frac{1}{16}

x^{2} - 4 x - 8 y + 28 = 0

x^{2} + (y + 4) = 10

4 x^{2} + 25 y - 8 x + 200 y + 304 = 0

y^{1} = 8 y - 64 x^{2} + 6

(y - 6)^{2} = 32 (x + 1)

What is -f(x)=4x^2+4x-3 ?
The solution to -f(x)=4x^2+4x-3 is Parabola with (h,k)=(-1/2 ,4),p=-1/16