What is (x-2)^2-((y-1)^2)/4 =1 ?

The solution to (x-2)^2-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(2,1),a=1,b=2

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(x-2)^2-((y-1)^2)/4 =1

(x - 2)^{2} - \frac{( y - 1 ) ^{2}}{4} = 1

(h, k) = (2, 1), a = 1, b = 2

Solution steps

(x - 2)^{2} - \frac{( y - 1 ) ^{2}}{4} = 1

Rewrite

(x - 2)^{2} - \frac{( y - 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{1 ^{2}} - \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 1), a = 1, b = 2

\frac{( x + 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

y^{2} - 4 x^{2} < 1

4 x^{2} - y^{2} - 2 y = 2

[f (x)]^{2} = 4 x^{2} - x + 4

What is (x-2)^2-((y-1)^2)/4 =1 ?
The solution to (x-2)^2-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(2,1),a=1,b=2