What is -x^2+4y^2-1=0 ?

The solution to -x^2+4y^2-1=0 is Hyperbola with (h,k)=(0,0),a= 1/2 ,b=1

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-x^2+4y^2-1=0

- x^{2} + 4 y^{2} - 1 = 0

(h, k) = (0, 0), a = \frac{1}{2}, b = 1

Solution steps

- x^{2} + 4 y^{2} - 1 = 0

Rewrite

- x^{2} + 4 y^{2} - 1 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} - \frac{( x - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{1}{2}, b = 1

\frac{( y - 4 ) ^{2}}{36} - x^{2} = 1

x^{2} - y^{2} - 2 x + 4 y - 4 = 0

(x - y - 3) \cdot (x + y + 3) = 16

y^{2} - 3 y - 2 = x^{2}

\frac{( x + 1 ) ^{2}}{2} - \frac{( y - 2 ) ^{2}}{1} = 1

What is -x^2+4y^2-1=0 ?
The solution to -x^2+4y^2-1=0 is Hyperbola with (h,k)=(0,0),a= 1/2 ,b=1