What is 8^2+(x-2)^2=y^2 ?

The solution to 8^2+(x-2)^2=y^2 is Hyperbola with (h,k)=(2,0),a=8,b=8

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8^2+(x-2)^2=y^2

8^{2} + (x - 2)^{2} = y^{2}

(h, k) = (2, 0), a = 8, b = 8

Solution steps

8^{2} + (x - 2)^{2} = y^{2}

Rewrite

8^{2} + (x - 2)^{2} - y^{2} = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{8 ^{2}} - \frac{( x - 2 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 0), a = 8, b = 8

- \frac{9}{5} + 2 x + x^{2} - \frac{6 y}{5} - \frac{y ^{2}}{5} = 0

y^{2} = (x - 4) (x + 3)

240 0^{2} x^{2} = 46 0^{2} (x^{2} + z^{2} + 36)

24 = a^{2} - b^{2}

9 x^{2} - 25 y^{2} + 200 y = 625

What is 8^2+(x-2)^2=y^2 ?
The solution to 8^2+(x-2)^2=y^2 is Hyperbola with (h,k)=(2,0),a=8,b=8