What is -9/5+2x+x^2-(6y)/5-(y^2)/5 =0 ?

The solution to -9/5+2x+x^2-(6y)/5-(y^2)/5 =0 is Hyperbola with (h,k)=(-1,-3),a=1,b=sqrt(5)

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-9/5+2x+x^2-(6y)/5-(y^2)/5 =0

- \frac{9}{5} + 2 x + x^{2} - \frac{6 y}{5} - \frac{y ^{2}}{5} = 0

(h, k) = (- 1, - 3), a = 1, b = 5

Solution steps

- \frac{9}{5} + 2 x + x^{2} - \frac{6 y}{5} - \frac{y ^{2}}{5} = 0

Rewrite

- \frac{9}{5} + 2 x + x^{2} - \frac{6 y}{5} - \frac{y ^{2}}{5} = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{1 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{( 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, - 3), a = 1, b = 5

y^{2} = (x - 4) (x + 3)

240 0^{2} x^{2} = 46 0^{2} (x^{2} + z^{2} + 36)

24 = a^{2} - b^{2}

9 x^{2} - 25 y^{2} + 200 y = 625

f (x) (f (x)) = x^{2} + \frac{1}{4}

What is -9/5+2x+x^2-(6y)/5-(y^2)/5 =0 ?
The solution to -9/5+2x+x^2-(6y)/5-(y^2)/5 =0 is Hyperbola with (h,k)=(-1,-3),a=1,b=sqrt(5)