What is 3x^2-4y^2=12 ?

The solution to 3x^2-4y^2=12 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(3)

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3x^2-4y^2=12

3 x^{2} - 4 y^{2} = 12

(h, k) = (0, 0), a = 2, b = 3

Solution steps

3 x^{2} - 4 y^{2} = 12

Rewrite

3 x^{2} - 4 y^{2} = 12

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 3

- x^{2} + 4 y^{2} = 16

x^{2} - 10 x - 4 y^{2} - 8 y + 17 = 0

y^{2} - x^{2} - 9 = 0

9 x^{2} - y^{2} - 36 x - 2 y + 44 = 0

t^{2} = 27 + u^{2}

What is 3x^2-4y^2=12 ?
The solution to 3x^2-4y^2=12 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(3)