What is ((x+2)^2)/4-(y+4)^2=1 ?

The solution to ((x+2)^2)/4-(y+4)^2=1 is Hyperbola with (h,k)=(-2,-4),a=2,b=1

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((x+2)^2)/4-(y+4)^2=1

\frac{( x + 2 ) ^{2}}{4} - (y + 4)^{2} = 1

(h, k) = (- 2, - 4), a = 2, b = 1

Solution steps

\frac{( x + 2 ) ^{2}}{4} - (y + 4)^{2} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{4} - (y + 4)^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} - \frac{( y - ( - 4 ) ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 4), a = 2, b = 1

(x - 2 y) (x + 2 y) = 4

16 x^{2} - 3 y^{2} - 32 x + 12 y - 44 = 0

\frac{( y + 1 ) ^{2}}{36} - \frac{( x - 4 ) ^{2}}{4} = 1

\frac{y ^{2}}{100} - \frac{x ^{2}}{64} = 1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

What is ((x+2)^2)/4-(y+4)^2=1 ?
The solution to ((x+2)^2)/4-(y+4)^2=1 is Hyperbola with (h,k)=(-2,-4),a=2,b=1