What is 16x^2-3y^2-32x+12y-44=0 ?

The solution to 16x^2-3y^2-32x+12y-44=0 is Hyperbola with (h,k)=(1,2),a=sqrt(3),b=4

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16x^2-3y^2-32x+12y-44=0

16 x^{2} - 3 y^{2} - 32 x + 12 y - 44 = 0

(h, k) = (1, 2), a = 3, b = 4

Solution steps

16 x^{2} - 3 y^{2} - 32 x + 12 y - 44 = 0

Rewrite

16 x^{2} - 3 y^{2} - 32 x + 12 y - 44 = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{( 3 ) ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 3, b = 4

\frac{( y + 1 ) ^{2}}{36} - \frac{( x - 4 ) ^{2}}{4} = 1

\frac{y ^{2}}{100} - \frac{x ^{2}}{64} = 1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

y^{2} = (x - 4)^{2} - 1

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

What is 16x^2-3y^2-32x+12y-44=0 ?
The solution to 16x^2-3y^2-32x+12y-44=0 is Hyperbola with (h,k)=(1,2),a=sqrt(3),b=4