What is x^2-4y^2+16=0 ?

The solution to x^2-4y^2+16=0 is Hyperbola with (h,k)=(0,0),a=2,b=4

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x^2-4y^2+16=0

x^{2} - 4 y^{2} + 16 = 0

(h, k) = (0, 0), a = 2, b = 4

Solution steps

x^{2} - 4 y^{2} + 16 = 0

Rewrite

x^{2} - 4 y^{2} + 16 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 4

9 x^{2} - 54 x + 9 - 4 y^{2} - 8 y - 113 = 0

y^{2} = 9 (1 + x^{2})

\frac{x ^{2}}{12} - \frac{y ^{2}}{16} = 1

244 - 98 y + 324 x - 49 y^{2} + 81 x^{2} = 0

3 a^{2} - 20 b^{2} - 100 = 0

What is x^2-4y^2+16=0 ?
The solution to x^2-4y^2+16=0 is Hyperbola with (h,k)=(0,0),a=2,b=4