What is y^2=9(1+x^2) ?

The solution to y^2=9(1+x^2) is Hyperbola with (h,k)=(0,0),a=3,b=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2=9(1+x^2)

y^{2} = 9 (1 + x^{2})

(h, k) = (0, 0), a = 3, b = 1

Solution steps

y^{2} = 9 (1 + x^{2})

Rewrite

y^{2} - 9 (1 + x^{2}) = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{3 ^{2}} - \frac{( x - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 1

\frac{x ^{2}}{12} - \frac{y ^{2}}{16} = 1

244 - 98 y + 324 x - 49 y^{2} + 81 x^{2} = 0

3 a^{2} - 20 b^{2} - 100 = 0

x^{2} - 6 x + 8 y - y^{2} = 0

c^{2} = 5^{2} + a^{2}

What is y^2=9(1+x^2) ?
The solution to y^2=9(1+x^2) is Hyperbola with (h,k)=(0,0),a=3,b=1