What is (x-3)^2-(y^2)/9 =1 ?

The solution to (x-3)^2-(y^2)/9 =1 is Hyperbola with (h,k)=(3,0),a=1,b=3

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(x-3)^2-(y^2)/9 =1

(x - 3)^{2} - \frac{y ^{2}}{9} = 1

(h, k) = (3, 0), a = 1, b = 3

Solution steps

(x - 3)^{2} - \frac{y ^{2}}{9} = 1

Rewrite

(x - 3)^{2} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 0), a = 1, b = 3

8 x^{2} - 9 y^{2} - 63 x - 18 y + 65 = 0

s^{2} = d^{2} + 2^{2}

2 x^{(2)} - 4 y^{(2)} = 16

4 x^{2} - 25 y^{2} + 8 x - 100 y - 196 = 0

x, x \cdot (x + 1) = h (x)^{2}

What is (x-3)^2-(y^2)/9 =1 ?
The solution to (x-3)^2-(y^2)/9 =1 is Hyperbola with (h,k)=(3,0),a=1,b=3