What is 2x^{(2)}-4y^{(2)}=16 ?

The solution to 2x^{(2)}-4y^{(2)}=16 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2

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2x^{(2)}-4y^{(2)}=16

2 x^{(2)} - 4 y^{(2)} = 16

(h, k) = (0, 0), a = 22, b = 2

Solution steps

2 x^{2} - 4 y^{2} = 16

Rewrite

2 x^{2} - 4 y^{2} = 16

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 22, b = 2

4 x^{2} - 25 y^{2} + 8 x - 100 y - 196 = 0

x, x \cdot (x + 1) = h (x)^{2}

- x^{2} + 2 y^{2} - 20 y - 6 = 0

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 2 ) ^{2}}{32} = 1

- x^{2} + 9 y^{2} - 36 y + 27 = 0

What is 2x^{(2)}-4y^{(2)}=16 ?
The solution to 2x^{(2)}-4y^{(2)}=16 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2