What is ((y+5)^2)/4-((x+2)^2)/9 =1 ?

The solution to ((y+5)^2)/4-((x+2)^2)/9 =1 is Hyperbola with (h,k)=(-2,-5),a=2,b=3

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((y+5)^2)/4-((x+2)^2)/9 =1

\frac{( y + 5 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{9} = 1

(h, k) = (- 2, - 5), a = 2, b = 3

Solution steps

\frac{( y + 5 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{9} = 1

Rewrite

\frac{( y + 5 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 5 ) ) ^{2}}{2 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 5), a = 2, b = 3

\frac{( x - 6 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

25 x^{2} - 32 y^{2} - 800 = 0

3 x^{2} - 3 y^{2} - 2 x + y - 6 = 0

\frac{( x - 1 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

[f (x)]^{2} = 3 x^{2} - 5 x + 4

What is ((y+5)^2)/4-((x+2)^2)/9 =1 ?
The solution to ((y+5)^2)/4-((x+2)^2)/9 =1 is Hyperbola with (h,k)=(-2,-5),a=2,b=3