Solution
Solution
Solution steps
Rewrite in the form of a standard hyperbola equation
Therefore Hyperbola properties are:
Popular Examples
25x^2-32y^2-800=03x^2-3y^2-2x+y-6=0((x-1)^2}{16}-\frac{(y-2)^2)/9 =1[f(x)]^2=3x^2-5x+4-(x^2}{25}+\frac{y^2)/9 =1
Frequently Asked Questions (FAQ)
What is ((x-6)^2)/4-(y^2)/9 =1 ?
The solution to ((x-6)^2)/4-(y^2)/9 =1 is Hyperbola with (h,k)=(6,0),a=2,b=3