What is ((x-1)^2}{16}-\frac{(y-2)^2)/9 =1 ?

The solution to ((x-1)^2}{16}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(1,2),a=4,b=3

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((x-1)^2}{16}-\frac{(y-2)^2)/9 =1

\frac{( x - 1 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

(h, k) = (1, 2), a = 4, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 4, b = 3

[f (x)]^{2} = 3 x^{2} - 5 x + 4

- \frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

y^{2} + 4 y - 3 x^{2} + 6 x + 4 = 0

3 x^{2} - 2 y^{2} = 4

(x + y) (x - y) = 1

What is ((x-1)^2}{16}-\frac{(y-2)^2)/9 =1 ?
The solution to ((x-1)^2}{16}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(1,2),a=4,b=3