What is -(x^2}{25}+\frac{y^2)/9 =1 ?

The solution to -(x^2}{25}+\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=3,b=5

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-(x^2}{25}+\frac{y^2)/9 =1

- \frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 3, b = 5

Solution steps

- \frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

Rewrite

- \frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{3 ^{2}} - \frac{( x - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 5

y^{2} + 4 y - 3 x^{2} + 6 x + 4 = 0

3 x^{2} - 2 y^{2} = 4

(x + y) (x - y) = 1

\frac{( y + 2 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

18 x^{2} - 9 y^{2} - 96 x - 36 y - 36 = 0

What is -(x^2}{25}+\frac{y^2)/9 =1 ?
The solution to -(x^2}{25}+\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=3,b=5