What is (((x-2)}{16})^2-\frac{(y+3)^2)/1 =1 ?

The solution to (((x-2)}{16})^2-\frac{(y+3)^2)/1 =1 is Hyperbola with (h,k)=(2,-3),a=16,b=1

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(((x-2)}{16})^2-\frac{(y+3)^2)/1 =1

(\frac{( x - 2 )}{16})^{2} - \frac{( y + 3 ) ^{2}}{1} = 1

(h, k) = (2, - 3), a = 16, b = 1

Solution steps

(\frac{x - 2}{16})^{2} - \frac{( y + 3 ) ^{2}}{1} = 1

Rewrite

(\frac{x - 2}{16})^{2} - \frac{( y + 3 ) ^{2}}{1} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{1 6 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 3), a = 16, b = 1

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

25 x^{2} - 36 y^{2} - 200 x + 360 y - 1400 = 0

25 y^{2} - 9 x^{2} + 18 x - 50 y = 241

\frac{y ^{2}}{4} - \frac{x ^{2}}{6} = 1

What is (((x-2)}{16})^2-\frac{(y+3)^2)/1 =1 ?
The solution to (((x-2)}{16})^2-\frac{(y+3)^2)/1 =1 is Hyperbola with (h,k)=(2,-3),a=16,b=1