What is -4x^2+y^2-40x-16=0 ?

The solution to -4x^2+y^2-40x-16=0 is Hyperbola with (h,k)=(-5,0),a=sqrt(21),b=2sqrt(21)

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-4x^2+y^2-40x-16=0

- 4 x^{2} + y^{2} - 40 x - 16 = 0

(h, k) = (- 5, 0), a = 21, b = 221

Solution steps

- 4 x^{2} + y^{2} - 40 x - 16 = 0

Rewrite

- 4 x^{2} + y^{2} - 40 x - 16 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{( 21 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 21 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 0), a = 21, b = 221

x^{2} + 8 x - y^{2} - 4 y = 5

- 9 y^{2} + 9 z^{2} = 4

\frac{y ^{2}}{6} - \frac{x ^{2}}{3} = 1

y^{2} - 2 x^{2} - 4 x - 4 y = 8

x^{2} - y^{2} + 8 x + 24 y = 0

What is -4x^2+y^2-40x-16=0 ?
The solution to -4x^2+y^2-40x-16=0 is Hyperbola with (h,k)=(-5,0),a=sqrt(21),b=2sqrt(21)