What is x^2+8x-y^2-4y=5 ?

The solution to x^2+8x-y^2-4y=5 is Hyperbola with (h,k)=(-4,-2),a=sqrt(17),b=sqrt(17)

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x^2+8x-y^2-4y=5

x^{2} + 8 x - y^{2} - 4 y = 5

(h, k) = (- 4, - 2), a = 17, b = 17

Solution steps

x^{2} + 8 x - y^{2} - 4 y = 5

Rewrite

x^{2} + 8 x - y^{2} - 4 y = 5

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{( 17 ) ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{( 17 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 2), a = 17, b = 17

- 9 y^{2} + 9 z^{2} = 4

\frac{y ^{2}}{6} - \frac{x ^{2}}{3} = 1

y^{2} - 2 x^{2} - 4 x - 4 y = 8

x^{2} - y^{2} + 8 x + 24 y = 0

\frac{( x - 9 ) ^{2}}{16} - \frac{( y - 11 ) ^{2}}{9} = 1

What is x^2+8x-y^2-4y=5 ?
The solution to x^2+8x-y^2-4y=5 is Hyperbola with (h,k)=(-4,-2),a=sqrt(17),b=sqrt(17)