What is ((x+1)^2)/9-((y-3)^2)/4 =1 ?

The solution to ((x+1)^2)/9-((y-3)^2)/4 =1 is Hyperbola with (h,k)=(-1,3),a=3,b=2

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((x+1)^2)/9-((y-3)^2)/4 =1

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{4} = 1

(h, k) = (- 1, 3), a = 3, b = 2

Solution steps

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{3 ^{2}} - \frac{( y - 3 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 3), a = 3, b = 2

[f (x)]^{2} = 2 x^{2} - x + 5

\frac{( x + 4 ) ^{2}}{64} - \frac{( y + 5 ) ^{2}}{81} = 1

3 x^{(2)} - 12 y^{(2)} + 48 = 0

- 9 y^{2} + z^{2} = 36

3 x^{2} - y^{2} + 3 x + 4 y - 3 = 0

What is ((x+1)^2)/9-((y-3)^2)/4 =1 ?
The solution to ((x+1)^2)/9-((y-3)^2)/4 =1 is Hyperbola with (h,k)=(-1,3),a=3,b=2