What is (8(x+7)^2-12(y-5)^2)/(96)=1 ?

The solution to (8(x+7)^2-12(y-5)^2)/(96)=1 is Hyperbola with (h,k)=(-7,5),a=2sqrt(3),b=2sqrt(2)

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(8(x+7)^2-12(y-5)^2)/(96)=1

\frac{8 ( x + 7 ) ^{2} - 12 ( y - 5 ) ^{2}}{96} = 1

(h, k) = (- 7, 5), a = 23, b = 22

Solution steps

\frac{8 ( x + 7 ) ^{2} - 12 ( y - 5 ) ^{2}}{96} = 1

Rewrite

\frac{8 ( x + 7 ) ^{2} - 12 ( y - 5 ) ^{2}}{96} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 7 ) ) ^{2}}{( 2 3 ) ^{2}} - \frac{( y - 5 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 7, 5), a = 23, b = 22

\frac{x ^{2}}{180} - \frac{( y + 1 ) ^{2}}{100} = 1

\frac{( x - 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{3} = 1

\frac{x ^{2} - y ^{2}}{11 \cdot 2} = 4

y^{2} - (x + 1)^{2} = 3

y \frac{y}{x} + 1 = x

What is (8(x+7)^2-12(y-5)^2)/(96)=1 ?
The solution to (8(x+7)^2-12(y-5)^2)/(96)=1 is Hyperbola with (h,k)=(-7,5),a=2sqrt(3),b=2sqrt(2)