What is (x^2)/(180)-((y+1)^2)/(100)=1 ?

The solution to (x^2)/(180)-((y+1)^2)/(100)=1 is Hyperbola with (h,k)=(0,-1),a=6sqrt(5),b=10

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(x^2)/(180)-((y+1)^2)/(100)=1

\frac{x ^{2}}{180} - \frac{( y + 1 ) ^{2}}{100} = 1

(h, k) = (0, - 1), a = 65, b = 10

Solution steps

\frac{x ^{2}}{180} - \frac{( y + 1 ) ^{2}}{100} = 1

Rewrite

\frac{x ^{2}}{180} - \frac{( y + 1 ) ^{2}}{100} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 6 5 ) ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{1 0 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 1), a = 65, b = 10

\frac{( x - 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{3} = 1

\frac{x ^{2} - y ^{2}}{11 \cdot 2} = 4

y^{2} - (x + 1)^{2} = 3

y \frac{y}{x} + 1 = x

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 6 ) ^{2}}{49} = 1

What is (x^2)/(180)-((y+1)^2)/(100)=1 ?
The solution to (x^2)/(180)-((y+1)^2)/(100)=1 is Hyperbola with (h,k)=(0,-1),a=6sqrt(5),b=10