What is (((x+1))/(16))^2-(((y-4))/(25))^2=1 ?

The solution to (((x+1))/(16))^2-(((y-4))/(25))^2=1 is Hyperbola with (h,k)=(-1,4),a=16,b=25

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(((x+1))/(16))^2-(((y-4))/(25))^2=1

(\frac{( x + 1 )}{16})^{2} - (\frac{( y - 4 )}{25})^{2} = 1

(h, k) = (- 1, 4), a = 16, b = 25

Solution steps

(\frac{x + 1}{16})^{2} - (\frac{y - 4}{25})^{2} = 1

Rewrite

(\frac{x + 1}{16})^{2} - (\frac{y - 4}{25})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{1 6 ^{2}} - \frac{( y - 4 ) ^{2}}{2 5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 16, b = 25

x^{2} - 4 y^{2} - 4 x - 12 = 0

x^{2} - y^{2} + 2 x - 5 y + 10 = 0

- 8 x^{2} + y^{2} - 36 x + 6 y - 27 = 0

x^{2} + 1 - 2 y^{2} = 0

9 y^{2} - 16 x^{2} - 18 y - 64 x - 199 = 0

What is (((x+1))/(16))^2-(((y-4))/(25))^2=1 ?
The solution to (((x+1))/(16))^2-(((y-4))/(25))^2=1 is Hyperbola with (h,k)=(-1,4),a=16,b=25