What is ((x-5)^2)/(4^2)-((y-2)^2)/(2^2)=1 ?

The solution to ((x-5)^2)/(4^2)-((y-2)^2)/(2^2)=1 is Hyperbola with (h,k)=(5,2),a=4,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-5)^2)/(4^2)-((y-2)^2)/(2^2)=1

\frac{( x - 5 ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

(h, k) = (5, 2), a = 4, b = 2

Solution steps

\frac{( x - 5 ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 2), a = 4, b = 2

3 y^{2} - 3 x^{2} + 5 x + 10 y = 5 x^{2} + 1

x^{2} + 8 x - y^{2} - 9 y = 6

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1

(\frac{3 y + 2 x}{18}) (\frac{3 y - 2 x}{2}) = 1

\frac{1 x ^{2}}{4} - \frac{y ^{2}}{16} = 1

What is ((x-5)^2)/(4^2)-((y-2)^2)/(2^2)=1 ?
The solution to ((x-5)^2)/(4^2)-((y-2)^2)/(2^2)=1 is Hyperbola with (h,k)=(5,2),a=4,b=2