What is (y^2)/(16)-(x^2)/(49)=1 ?

The solution to (y^2)/(16)-(x^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=4,b=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y^2)/(16)-(x^2)/(49)=1

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1

(h, k) = (0, 0), a = 4, b = 7

Solution steps

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1

Rewrite

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 7

(\frac{3 y + 2 x}{18}) (\frac{3 y - 2 x}{2}) = 1

\frac{1 x ^{2}}{4} - \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{20} - \frac{( y + 1 ) ^{2}}{10} = 1

4 x^{2} - 9 y^{2} = 1

\frac{( x - 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{36} = 1

What is (y^2)/(16)-(x^2)/(49)=1 ?
The solution to (y^2)/(16)-(x^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=4,b=7